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<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-0972843561-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-9842357610-3"><b>Question</b></h2><p>The difference between downstream speed and upstream speed of boat is 6 km/hr and boat travels 72 km from P to Q (downstream) in 4 hours. Then find the speed of boat in still water?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 33 Seconds </h3></div></div><b> Options :</b><ol><li style="color:green;"><p>15 km/hr</p>
</li><li style="color:red;"><p>18 km/hr</p>
</li><li style="color:red;"><p>20km/hr</p>
</li><li style="color:red;"><p>16 km/hr</p>
</li><li style="color:red;"><p>24 km/hr</p>
</li></ol> <h2 id="content-id-8639401257-4"><b>Solution</b></h2><p><span style="font-size:11pt"><span style="font-family:Calibri,">The correct answer is <strong>option 1 </strong>i.e.<strong> </strong></span></span><strong>15 km/hr</strong></p>

<p>Let the speed of boat in still water be x km/hr and that of stream be y km/hr</p>

<p>ATQ,</p>

<p>(x + y) – (x – y) = 6</p>

<p>⇒ 2y = 6 ⇒ y = 3 km/hr</p>

<p>Downstream stream = (x + y) = 72/4 = 18 km/hr</p>

<p>⇒ x = 15 km/hr</p>
</body></html>


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The difference between downstream - Trigonometry Questions for Banking

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-5312087469-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-9136452087-3"><b>Question</b></h2><p>In a vessel, there are two types of liquids A and B in the ratio of 5 : 9. 28 lit of the mixture is taken out and 2 lit of type B liquid is poured into it, the new ratio(A:B) thus formed is 1 : 2. Find the initial quanty of mixture in the vessel?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 37 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>84 lit</p>
</li><li style="color:red;"><p>42 lit</p>
</li><li style="color:red;"><p>50 lit</p>
</li><li style="color:green;"><p>56 lit</p>
</li><li style="color:red;"><p>70 lit</p>
</li></ol> <h2 id="content-id-9126478053-4"><b>Solution</b></h2><p>The correct answer is <strong>option 4 </strong>i.e. <strong>56 lit</strong></p>

<p>Let the initial quantity of mixture in vessel be x</p>

<p>lit</p>

<p>ATQ,</p>

<p>(x×<span class="math-tex">\(\frac{5}{14}\)</span>-10)(x×<span class="math-tex">\(\frac{9}{14}\)</span>-18+2) = 1/2</p>

<p>⇒ (5x-140)/(9x-224) = 1/2</p>

<p>⇒ 10x - 280 = 9x - 224</p>

<p>⇒ x = 56 lit</p>
</body></html>


In a vessel there are two - Trigonometry Questions for Banking

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-7540361289-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-7035184692-3"><b>Question</b></h2><p>The average weight of 5 students in a class is 25.8 kg. When a new student joined them, the average weight is increased by 3.9 kg. Then find the approximate weight of the new studen.
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 32 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>55 kg</p>
</li><li style="color:green;"><p>49 kg</p>
</li><li style="color:red;"><p>42 kg</p>
</li><li style="color:red;"><p>44 kg</p>
</li><li style="color:red;"><p>58 kg</p>
</li></ol> <h2 id="content-id-1073685249-4"><b>Solution</b></h2><p><span style="font-size:11pt"><span style="font-family:Calibri,">The correct answer is <strong>option 2 </strong>i.e. </span></span><strong>49 kg</strong></p>

<p>Weight of new student = 6 × (25.8 + 3.9) – 5 ×</p>

<p>25.8</p>

<p>≈ 49 kg</p>
</body></html>


The average weight of 5 students - Trigonometry Questions for Banking

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-2564930781-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-5470236198-3"><b>Question</b></h2><p>A person has purchased two adjacent plots, one is in rectangular shape and other is in square shape and combined them to make a single new plot. The breadth of the rectangular plot is equal to the side of the square plot and the cost of fencing the new plot is Rs. 390 (Rs. 5/m). Find the side of square if the length of the rectangular plot is 15 m.
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 42 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>10 m</p>
</li><li style="color:red;"><p>8 m</p>
</li><li style="color:green;"><p>12 m</p>
</li><li style="color:red;"><p>9 m</p>
</li><li style="color:red;"><p>6 m</p>
</li></ol> <h2 id="content-id-8795143206-4"><b>Solution</b></h2><p><span style="font-size:11pt"><span style="font-family:Calibri,">The correct answer is <strong>option 3 </strong>i.e. <strong>12 m</strong></span></span></p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/deepaksharma_14.01.2022_D2.png" style="height:129px; width:199px"></p>

<p>Let the breadth of rectangular plot be y m and</p>

<p>length = 15 m</p>

<p>ATQ,</p>

<p>30 + y + 3y = 390/5</p>

<p>⇒ 30 + 4y = 78</p>

<p>⇒ 4y = 48 ⇒ y = 12 m</p>
</body></html>


A person has purchased two - Trigonometry Questions for Banking

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-4289167035-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-6893745102-3"><b>Question</b></h2><p>A shopkeeper marked his article 50% above the cost price and gives a discount of 20% on it. If he had marked his article 75% above the cost price and gives a discount of 20% on it then find the earlier profit is what percent of the profit earned latter?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 36 Seconds </h3></div></div><b> Options :</b><ol><li style="color:green;"><p>50%</p>
</li><li style="color:red;"><p>60%</p>
</li><li style="color:red;"><p>33<span class="math-tex">\(\frac{1}{3}\)</span>%</p>
</li><li style="color:red;"><p>40%</p>
</li><li style="color:red;"><p>75%</p>
</li></ol> <h2 id="content-id-6581723409-4"><b>Solution</b></h2><p><span style="font-size:11pt"><span style="font-family:Calibri,">The correct answer is <strong>option 1 </strong>i.e. <strong>50 %</strong></span></span></p>

<p>Let the CP be Rs. 100x</p>

<p>Then, MP = Rs. 150x</p>

<p>SP = 150x ×(80/100)= Rs.120x</p>

<p>Profits = Rs. 20x</p>

<p>New MP = Rs. 175x</p>

<p>New SP = 175x×(80/100)= Rs.140x</p>

<p>New Profit = Rs. 40x</p>

<p>Required % = (20ð&#157;&#145;¥)/(40ð&#157;&#145;¥)×100 = 50%</p>
</body></html>


A shopkeeper marked his article - Trigonometry Questions for Banking

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-5478603291-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-5021368749-3"><b>Question</b></h2><p> A person invested two equal amounts in two different schemes. In first scheme, amount is invested at 8% p.a. on SI for T years and SI received is Rs 2000 while in second scheme, amount is invested at 10% p.a. for 2 years at CI and the compound interest received is Rs. 1050. Find the value of T
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 39 Seconds </h3></div></div><b> Options :</b><ol><li style="color:green;"><p>4 yr</p>
</li><li style="color:red;"><p>8 yr</p>
</li><li style="color:red;"><p>6 yr</p>
</li><li style="color:red;"><p>5 yr</p>
</li><li style="color:red;"><p>3 yr</p>
</li></ol> <h2 id="content-id-1648395207-4"><b>Solution</b></h2><p><span style="font-size:11pt"><span style='font-family:Calibri,"sans-serif"'>The correct answer is <strong><span style='font-family:"Calibri","sans-serif"'>option 1 </span></strong>i.e. <strong>4 yr</strong></span></span></p>

<p>Let the amount be Rs. x</p>

<p>CI at 10% in 2 years = 10 + 10 + (10 × 10)/100</p>

<p>= 21%.</p>

<p>ATQ,</p>

<p>(ð&#157;&#145;¥ × 21)/100 = 1050 ⇒ x = Rs. 5000</p>

<p>And,</p>

<p>(5000 × 8 × ð&#157;&#145;&#135;)/100 = 2000</p>

<p>⇒ T = 5 years.</p>
</body></html>


 A person invested two equal - Trigonometry Questions for Banking

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-7695283014-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-6981430257-3"><b>Trigonometry Questions</b></h2><p>Directions: Study the following paragraph carefully & answer the question given below.

There are 1000 students in a college. Out of 1000 students some appeared in exams ‘X’, ‘Y’ and ‘Z’ while some not. Number of student not appeared in any exam is equal to number of students appeared in exam ‘Z’ only. Number of students appeared in exam ‘Y’ is 360. Ratio of number of students appeared in exam ‘X’ and ‘Y’ only to number of students appeared in exam ‘Y’ and ‘Z’ only is 2 : 3. Number of student appeared in exam ‘X’ and ‘Z’ both is half of number of students appeared in only exam ‘Z’. Number of students appeared in exam ‘X’ only is 50% more than number of students appeared in ‘Y’ only. Number of students appeared in all the three exam is 4% of the total number of students in the college. Number of students appeared in ‘Y’ exam only is same as number of students appeared in ‘Y’ and ‘Z’ only. 56. How many students appeared in at least two exams?
</p><h2 id="content-id-9573420681-4"><b>Question</b></h2><p>How many students appeared in two exams only?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 81 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>280</p>
</li><li style="color:red;"><p>220</p>
</li><li style="color:red;"><p>340</p>
</li><li style="color:red;"><p>300</p>
</li><li style="color:green;"><p>960</p>
</li></ol> <h2 id="content-id-8913405627-5"><b>Solution</b></h2><p>The correct answer is <strong>option 5  </strong>i.e. <strong>960</strong></p>

<p>Total students = 1000 Let, students appear in exam Z only = a Total students appeared in exam Y = 360 Ratio of number of students appeared in exam X and Y only to students appeared in exam Y and Z only = 2 : 3 Students appeared in exam X and Z both = a/2</p>

<p>Number of students appeared in all three exams = 4/100 × 1000 = 40</p>

<p>Number of students appeared in Y exam only = No. of students appeared in Y and Z only = 3x</p>

<p>Number of students appeared in exam X and Y only</p>

<p>= 2/3 × 3ð&#157;&#145;¥ = 2X</p>

<p>1000</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/deepaksharma_14.01.2022_D3.png"></p>

<p>Now, 2x + 3x + 3x + 40 = 360</p>

<p>⇒ x = 40</p>

<p>and, 12.5x + a + a/2 + a = 1000</p>

<p>5a/2 = 500</p>

<p>⇒ a = 200</p>

<p>1000</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/deepaksharma_14.01.2022_D4.png"></p>

<p>Students appeared in two exams only = 80 + 60</p>

<p>+ 120 = 260</p>
</body></html>


How many students appeared - Trigonometry Questions for Banking

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-5096781243-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-8967105423-3"><b>Trigonometry Questions</b></h2><p>Directions: Study the following paragraph carefully & answer the question given below.

There are 1000 students in a college. Out of 1000 students some appeared in exams ‘X’, ‘Y’ and ‘Z’ while some not. Number of student not appeared in any exam is equal to number of students appeared in exam ‘Z’ only. Number of students appeared in exam ‘Y’ is 360. Ratio of number of students appeared in exam ‘X’ and ‘Y’ only to number of students appeared in exam ‘Y’ and ‘Z’ only is 2 : 3. Number of student appeared in exam ‘X’ and ‘Z’ both is half of number of students appeared in only exam ‘Z’. Number of students appeared in exam ‘X’ only is 50% more than number of students appeared in ‘Y’ only. Number of students appeared in all the three exam is 4% of the total number of students in the college. Number of students appeared in ‘Y’ exam only is same as number of students appeared in ‘Y’ and ‘Z’ only. 56. How many students appeared in at least two exams?
</p><h2 id="content-id-5719064328-4"><b>Question</b></h2><p>How many students appeared in at least two exams ?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 82 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>240</p>
</li><li style="color:red;"><p>260</p>
</li><li style="color:green;"><p>300</p>
</li><li style="color:red;"><p>360</p>
</li><li style="color:red;"><p>500</p>
</li></ol> <h2 id="content-id-3105498627-5"><b>Solution</b></h2><p><span style="font-size:11pt"><span style="font-family:Calibri,">The correct answer is <strong>option 3  </strong>i.e. <strong>300</strong></span></span></p>

<p>Total students = 1000 Let, students appear in exam Z only = a Total students appeared in exam Y = 360 Ratio of number of students appeared in exam X and Y only to students appeared in exam Y and Z only = 2 : 3 Students appeared in exam X and Z both = a/2</p>

<p>Number of students appeared in all three exams = 4/100 × 1000 = 40</p>

<p>Number of students appeared in Y exam only = No. of students appeared in Y and Z only = 3x</p>

<p>Number of students appeared in exam X and Y only</p>

<p>= 2/3 × 3ð&#157;&#145;¥ = 2X</p>

<p>1000</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/deepaksharma_14.01.2022_D3.png"></p>

<p>Now, 2x + 3x + 3x + 40 = 360</p>

<p>⇒ x = 40</p>

<p>and, 12.5x + a + a/2 + a = 1000</p>

<p>5a/2 = 500</p>

<p>⇒ a = 200</p>

<p>1000</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/deepaksharma_14.01.2022_D4.png"></p>

<p>Students appeared in atleast two exams = 80 + 60 + 40 + 120</p>

<p>= 300</p>
</body></html>


<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-3762514809-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-2031947685-3"><b>Trigonometry Questions</b></h2><p>Directions: Study the following paragraph carefully & answer the question given below.

There are 1000 students in a college. Out of 1000 students some appeared in exams ‘X’, ‘Y’ and ‘Z’ while some not. Number of student not appeared in any exam is equal to number of students appeared in exam ‘Z’ only. Number of students appeared in exam ‘Y’ is 360. Ratio of number of students appeared in exam ‘X’ and ‘Y’ only to number of students appeared in exam ‘Y’ and ‘Z’ only is 2 : 3. Number of student appeared in exam ‘X’ and ‘Z’ both is half of number of students appeared in only exam ‘Z’. Number of students appeared in exam ‘X’ only is 50% more than number of students appeared in ‘Y’ only. Number of students appeared in all the three exam is 4% of the total number of students in the college. Number of students appeared in ‘Y’ exam only is same as number of students appeared in ‘Y’ and ‘Z’ only. 56. How many students appeared in at least two exams?
</p><h2 id="content-id-3254016789-4"><b>Question</b></h2><p>How many students appeared in at most two exams?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 82 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>240</p>
</li><li style="color:red;"><p>260</p>
</li><li style="color:red;"><p>300</p>
</li><li style="color:red;"><p>500</p>
</li><li style="color:green;"><p>960</p>
</li></ol> <h2 id="content-id-2943071568-5"><b>Solution</b></h2><p>The correct answer is <strong>option 5  </strong>i.e. <strong>960</strong></p>

<p>Total students = 1000 Let, students appear in exam Z only = a Total students appeared in exam Y = 360 Ratio of number of students appeared in exam X and Y only to students appeared in exam Y and Z only = 2 : 3 Students appeared in exam X and Z both = a/2</p>

<p>Number of students appeared in all three exams = 4/100 × 1000 = 40</p>

<p>Number of students appeared in Y exam only = No. of students appeared in Y and Z only = 3x</p>

<p>Number of students appeared in exam X and Y only</p>

<p>= 2/3 × 3ð&#157;&#145;¥ = 2X</p>

<p>1000</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/deepaksharma_14.01.2022_D3.png"></p>

<p>Now, 2x + 3x + 3x + 40 = 360</p>

<p>⇒ x = 40</p>

<p>and, 12.5x + a + a/2 + a = 1000</p>

<p>5a/2 = 500</p>

<p>⇒ a = 200</p>

<p>1000</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/deepaksharma_14.01.2022_D4.png"></p>

<p>Students appeared in atmost two exams = 180 + 120 + 200 + 60 + 80 + 120 + 200= 960</p>
</body></html>


<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-8265941037-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-2951473806-3"><b>Trigonometry Questions</b></h2><p>Directions: Study the following paragraph carefully & answer the question given below.

There are 1000 students in a college. Out of 1000 students some appeared in exams ‘X’, ‘Y’ and ‘Z’ while some not. Number of student not appeared in any exam is equal to number of students appeared in exam ‘Z’ only. Number of students appeared in exam ‘Y’ is 360. Ratio of number of students appeared in exam ‘X’ and ‘Y’ only to number of students appeared in exam ‘Y’ and ‘Z’ only is 2 : 3. Number of student appeared in exam ‘X’ and ‘Z’ both is half of number of students appeared in only exam ‘Z’. Number of students appeared in exam ‘X’ only is 50% more than number of students appeared in ‘Y’ only. Number of students appeared in all the three exam is 4% of the total number of students in the college. Number of students appeared in ‘Y’ exam only is same as number of students appeared in ‘Y’ and ‘Z’ only. 56. How many students appeared in at least two exams?
</p><h2 id="content-id-6054721839-4"><b>Question</b></h2><p>How many students not appeared in exam Y?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 81 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>440</p>
</li><li style="color:red;"><p>360</p>
</li><li style="color:red;"><p>540</p>
</li><li style="color:green;"><p>640</p>
</li><li style="color:red;"><p>None of these</p>
</li></ol> <h2 id="content-id-9473528106-5"><b>Solution</b></h2><p>The correct answer is <strong>option 4  </strong>i.e. <strong>640</strong></p>

<p>Total students = 1000 Let, students appear in exam Z only = a Total students appeared in exam Y = 360 Ratio of number of students appeared in exam X and Y only to students appeared in exam Y and Z only = 2 : 3 Students appeared in exam X and Z both = a/2</p>

<p>Number of students appeared in all three exams = 4/100 × 1000 = 40</p>

<p>Number of students appeared in Y exam only = No. of students appeared in Y and Z only = 3x</p>

<p>Number of students appeared in exam X and Y only</p>

<p>= 2/3 × 3ð&#157;&#145;¥ = 2X</p>

<p>1000</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/deepaksharma_14.01.2022_D3.png"></p>

<p>Now, 2x + 3x + 3x + 40 = 360</p>

<p>⇒ x = 40</p>

<p>and, 12.5x + a + a/2 + a = 1000</p>

<p>5a/2 = 500</p>

<p>⇒ a = 200</p>

<p>1000</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/deepaksharma_14.01.2022_D4.png"></p>

<p>Student not appeared in exam Y = 1000 – 360 =</p>

<p>640</p>
</body></html>


How many students not appeared - Trigonometry Questions for Banking

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-5296081437-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-2167049385-3"><b>Trigonometry Questions</b></h2><p>Directions: Study the following paragraph carefully & answer the question given below.

There are 1000 students in a college. Out of 1000 students some appeared in exams ‘X’, ‘Y’ and ‘Z’ while some not. Number of student not appeared in any exam is equal to number of students appeared in exam ‘Z’ only. Number of students appeared in exam ‘Y’ is 360. Ratio of number of students appeared in exam ‘X’ and ‘Y’ only to number of students appeared in exam ‘Y’ and ‘Z’ only is 2 : 3. Number of student appeared in exam ‘X’ and ‘Z’ both is half of number of students appeared in only exam ‘Z’. Number of students appeared in exam ‘X’ only is 50% more than number of students appeared in ‘Y’ only. Number of students appeared in all the three exam is 4% of the total number of students in the college. Number of students appeared in ‘Y’ exam only is same as number of students appeared in ‘Y’ and ‘Z’ only. 56. How many students appeared in at least two exams?
</p><h2 id="content-id-7136824509-4"><b>Question</b></h2><p>How many students appeared in exam X or in exam Z?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 82 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>240</p>
</li><li style="color:red;"><p>360</p>
</li><li style="color:red;"><p>500</p>
</li><li style="color:green;"><p>680</p>
</li><li style="color:red;"><p>760</p>
</li></ol> <h2 id="content-id-9873250641-5"><b>Solution</b></h2><p>The correct answer is <strong>option 4  </strong>i.e. <strong>680</strong></p>

<p>Total students = 1000 Let, students appear in exam Z only = a Total students appeared in exam Y = 360 Ratio of number of students appeared in exam X and Y only to students appeared in exam Y and Z only = 2 : 3 Students appeared in exam X and Z both = a/2</p>

<p>Number of students appeared in all three exams = 4/100 × 1000 = 40</p>

<p>Number of students appeared in Y exam only = No. of students appeared in Y and Z only = 3x</p>

<p>Number of students appeared in exam X and Y only</p>

<p>= 2/3 × 3ð&#157;&#145;¥ = 2X</p>

<p>1000</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/deepaksharma_14.01.2022_D3.png" style="height:193px; width:237px"></p>

<p>Now, 2x + 3x + 3x + 40 = 360</p>

<p>⇒ x = 40</p>

<p>and, 12.5x + a + a/2 + a = 1000</p>

<p>5a/2 = 500</p>

<p>⇒ a = 200</p>

<p>1000</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/deepaksharma_14.01.2022_D4.png"></p>

<p> Students appeared in exam X or in exam Z</p>

<p>= 180 + 60 + 40 + 80 + 200 + 120</p>

<p>= 680</p>
</body></html>


<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-1298640753-2"><b>Puzzle Questions Overview</b></h2><p>Puzzle Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Puzzle Questions.</p><h2 id="content-id-4573201968-3"><b>Puzzle Questions</b></h2><p>Direction: Read the given information carefully and answer the following questions.

There are 12 members viz. H, I, J, K, L, M, N, O, P, Q, R, and S are working in the company on different designations. The designations in decreasing order are Chairman, President, VP, CEO, COO, CFO, GM, Manager, Assistant manager (AM), Clerk, Trainee, and Peon such that Chairman is the seniormost designation and Peon is the juniormost designation. Some of them are male while some of them are female. Not more than 2 persons of the same gender are adjacent to each other. Only three people sit between J and L who is a female while only one people sit between H and P who is immediately senior to I who is not a President but I is not a female. M is junior to only three people who is a female and four people sit between M and O who is immediately senior to J. An equal number of persons are senior to K and junior to N who is a male. Only two people sit between H and K who is a female and her neighbors are not female. R is junior to S and senior to Q who is a female. O and P are the same gender as Q while J has the opposite gender.
</p><h2 id="content-id-0391862754-4"><b>Question</b></h2><p>How many people are male?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 88 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>4</p>
</li><li style="color:green;"><p>6</p>
</li><li style="color:red;"><p>8</p>
</li><li style="color:red;"><p>9</p>
</li><li style="color:red;"><p>5</p>
</li></ol> <h2 id="content-id-7601325894-5"><b>Solution</b></h2><p>The correct answer is <strong>Option 2</strong> i.e. <strong>6</strong></p>

<p>1. M is junior to only three people who is a female and four people sit between M and O who is immediately senior to J. (i.e. M is a CEO, O is an AM, and J is a Clerk)</p>

<p>2. Only three people sit between J and L who is a female while only one people sit between H and P who is immediately senior to I who is not a President but I is not a female. (i.e. L is a CFO, H is a COO, P is a GM, and I - Male is a manager)</p>

<table border="1" cellpadding="1" cellspacing="1" style="width:300px">
	<tbody>
		<tr>
			<td><strong>Designation</strong></td>
			<td><strong>Person</strong></td>
			<td><strong>Gender</strong></td>
		</tr>
		<tr>
			<td>Chairman</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>President</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>VP</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>CEO</td>
			<td>M</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>COO</td>
			<td>H</td>
			<td> </td>
		</tr>
		<tr>
			<td>CFO</td>
			<td>L</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>GM</td>
			<td>P</td>
			<td> </td>
		</tr>
		<tr>
			<td>Manager</td>
			<td>I</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>AM</td>
			<td>O</td>
			<td> </td>
		</tr>
		<tr>
			<td>Clerk</td>
			<td>J</td>
			<td> </td>
		</tr>
		<tr>
			<td>Trainee</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>Peon</td>
			<td> </td>
			<td> </td>
		</tr>
	</tbody>
</table>

<p>3. Only two people sit between H and K who is a female and her neighbors are not female. (i.e. K is a President and her neighbor are males)</p>

<p>4. An equal number of persons are senior to K and junior to N who is a male. (i.e. N - Trainee)</p>

<p>5. R is junior to S and senior to Q who is a female. (i.e. R - VP, S - Chairman, and Q - Peon)</p>

<p>6. O and P are the same genders as Q while J has the opposite gender. (i.e. O and P is female, and J is male)(So, the remaining person H is a male because not more than 2 persons of the same gender are adjacent to each other)</p>

<table border="1" cellpadding="1" cellspacing="1" style="width:300px">
	<tbody>
		<tr>
			<td><strong>Designation</strong></td>
			<td><strong>Person</strong></td>
			<td><strong>Gender</strong></td>
		</tr>
		<tr>
			<td>Chairman</td>
			<td>S</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>President</td>
			<td>K</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>VP</td>
			<td>R</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>CEO</td>
			<td>M</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>COO</td>
			<td>H</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>CFO</td>
			<td>L</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>GM</td>
			<td>P</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>Manager</td>
			<td>I</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>AM</td>
			<td>O</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>Clerk</td>
			<td>J</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>Trainee</td>
			<td>N</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>Peon</td>
			<td>Q</td>
			<td>Female</td>
		</tr>
	</tbody>
</table>

<p>This is our final arrangement.</p>

<p>Clearly, 6 people are male.</p>

<p>Hence, the correct answer is "<strong>6</strong>".</p>
</body></html>


How many people are male - Puzzle Questions for Banking

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-8690723541-2"><b>Puzzle Questions Overview</b></h2><p>Puzzle Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Puzzle Questions.</p><h2 id="content-id-2843609175-3"><b>Puzzle Questions</b></h2><p>Directions: Study the following data carefully and answer the given questions accordingly.

Eight people of a family are working in a company on different designations i.e. CMD (senior-most), MD, CEO, COO, AO, Manager, Admin, and Clerk (junior-most). There are three married couples. 

The brother of K is not the CEO. The mother of P is junior to her daughter. Three people are designated between M and his brother-in-law, who is not a Manager. Three people are designated between S and the wife of N. L is the sister-in-law of K. J is married to S, who is the sister of M, who is the nephew of N. U is junior to N but not immediately. P is the granddaughter of U and is junior to her father but not immediately. L is junior to the son of K but not immediately. The wife of J is junior to the Manager. U, who does not have a sibling, is the husband of K, who is the sister of N.
</p><h2 id="content-id-3271486059-4"><b>Question</b></h2><p>Who among the following is the Manager?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 75 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>J</p>
</li><li style="color:red;"><p>N</p>
</li><li style="color:green;"><p>U</p>
</li><li style="color:red;"><p>P</p>
</li><li style="color:red;"><p>None of these</p>
</li></ol> <h2 id="content-id-6851490273-5"><b>Solution</b></h2><p>The correct answer is <strong>Option 3</strong> i.e. <strong>U</strong></p>



<p>1. J is married to S, who is the sister of M, who is the nephew of N.</p>

<p>2. U, who does not have a sibling, is the husband of K, who is the sister of N.</p>

<p>3. L is the sister-in-law of K.</p>

<p>4. The wife of J is junior to the Manager.</p>

<p>5. Three people are designated between S and the wife of N.</p>

<p>6. P is the granddaughter of U.</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/IBPS%20PO%20MFT4_19.11.2020_D17.png" style="height:353px; width:300px"></p>

<p>7. L is junior to the son of K but not immediately.</p>

<p>8. Three people are designated between M and his brother-in-law, who is not a Manager.</p>

<p>9. P is junior to her father but not immediately.</p>

<p>10. The mother of P is junior to her daughter.</p>

<p>(Here, case 1 will be eliminated and we will continue with case 2)</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/IBPS%20PO%20MFT4_19.11.2020_D18.png" style="height:368px; width:300px"></p>

<p>11. U is junior to N but not immediately.</p>

<p>12. The brother of K is not the CEO.</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/IBPS%20PO%20MFT4_19.11.2020_D19.png" style="height:370px; width:300px"></p>

<p>Hence the correct answer is <strong>U.</strong></p>
</body></html>


Who among the following is - Puzzle Questions for Banking

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-9564723801-2"><b>Puzzle Questions Overview</b></h2><p>Puzzle Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Puzzle Questions.</p><h2 id="content-id-1089354726-3"><b>Puzzle Questions</b></h2><p>Directions: Study the following data carefully and answer the given questions accordingly.

Eight people of a family are working in a company on different designations i.e. CMD (senior-most), MD, CEO, COO, AO, Manager, Admin, and Clerk (junior-most). There are three married couples. 

The brother of K is not the CEO. The mother of P is junior to her daughter. Three people are designated between M and his brother-in-law, who is not a Manager. Three people are designated between S and the wife of N. L is the sister-in-law of K. J is married to S, who is the sister of M, who is the nephew of N. U is junior to N but not immediately. P is the granddaughter of U and is junior to her father but not immediately. L is junior to the son of K but not immediately. The wife of J is junior to the Manager. U, who does not have a sibling, is the husband of K, who is the sister of N.
</p><h2 id="content-id-1052396748-4"><b>Question</b></h2><p>Find the correct combination from the following.
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 75 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>CEO - J</p>
</li><li style="color:red;"><p>AO - L</p>
</li><li style="color:red;"><p>CMD - N</p>
</li><li style="color:red;"><p>Clerk - P</p>
</li><li style="color:green;"><p>None is correct</p>
</li></ol> <h2 id="content-id-7635980124-5"><b>Solution</b></h2><p>The correct answer is <strong>Option 5</strong> i.e. <strong>None is correct</strong></p>

<p>1. J is married to S, who is the sister of M, who is the nephew of N.</p>

<p>2. U, who does not have a sibling, is the husband of K, who is the sister of N.</p>

<p>3. L is the sister-in-law of K.</p>

<p>4. The wife of J is junior to the Manager.</p>

<p>5. Three people are designated between S and the wife of N.</p>

<p>6. P is the granddaughter of U.</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/IBPS%20PO%20MFT4_19.11.2020_D17.png" style="height:353px; width:300px"></p>

<p>7. L is junior to the son of K but not immediately.</p>

<p>8. Three people are designated between M and his brother-in-law, who is not a Manager.</p>

<p>9. P is junior to her father but not immediately.</p>

<p>10. The mother of P is junior to her daughter.</p>

<p>(Here, case 1 will be eliminated and we will continue with case 2)</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/IBPS%20PO%20MFT4_19.11.2020_D18.png" style="height:368px; width:300px"></p>

<p>11. U is junior to N but not immediately.</p>

<p>12. The brother of K is not the CEO.</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/IBPS%20PO%20MFT4_19.11.2020_D19.png" style="height:370px; width:300px"></p>

<p>Hence the correct answer is<strong> None is correct.</strong></p>
</body></html>


Find the correct combination - Puzzle Questions for Banking

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-7502634198-2"><b>Puzzle Questions Overview</b></h2><p>Puzzle Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Puzzle Questions.</p><h2 id="content-id-6350287491-3"><b>Puzzle Questions</b></h2><p>Directions: Study the following data carefully and answer the given questions accordingly.

Eight people of a family are working in a company on different designations i.e. CMD (senior-most), MD, CEO, COO, AO, Manager, Admin, and Clerk (junior-most). There are three married couples. 

The brother of K is not the CEO. The mother of P is junior to her daughter. Three people are designated between M and his brother-in-law, who is not a Manager. Three people are designated between S and the wife of N. L is the sister-in-law of K. J is married to S, who is the sister of M, who is the nephew of N. U is junior to N but not immediately. P is the granddaughter of U and is junior to her father but not immediately. L is junior to the son of K but not immediately. The wife of J is junior to the Manager. U, who does not have a sibling, is the husband of K, who is the sister of N.
</p><h2 id="content-id-8094356172-4"><b>Question</b></h2><p>Find the odd one from the following.
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 75 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>M, K</p>
</li><li style="color:red;"><p>S, U</p>
</li><li style="color:red;"><p>K, J</p>
</li><li style="color:red;"><p>L, N</p>
</li><li style="color:green;"><p>N, S</p>
</li></ol> <h2 id="content-id-6983547021-5"><b>Solution</b></h2><p>The correct answer is <strong>Option 5</strong> i.e. <strong>N, S</strong></p>

<p>1. J is married to S, who is the sister of M, who is the nephew of N.</p>

<p>2. U, who does not have a sibling, is the husband of K, who is the sister of N.</p>

<p>3. L is the sister-in-law of K.</p>

<p>4. The wife of J is junior to the Manager.</p>

<p>5. Three people are designated between S and the wife of N.</p>

<p>6. P is the granddaughter of U.</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/IBPS%20PO%20MFT4_19.11.2020_D17.png" style="height:294px; width:250px"></p>

<p>7. L is junior to the son of K but not immediately.</p>

<p>8. Three people are designated between M and his brother-in-law, who is not a Manager.</p>

<p>9. P is junior to her father but not immediately.</p>

<p>10. The mother of P is junior to her daughter.</p>

<p>(Here, case 1 will be eliminated and we will continue with case 2)</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/IBPS%20PO%20MFT4_19.11.2020_D18.png" style="height:306px; width:250px"></p>

<p>11. U is junior to N but not immediately.</p>

<p>12. The brother of K is not the CEO.</p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/IBPS%20PO%20MFT4_19.11.2020_D19.png" style="height:309px; width:250px"></p>

<p>From the above arrangement, More than one person is designated between N and S.</p>

<p>Hence the correct answer is<strong> N, S</strong></p>
</body></html>


Find the odd one from the - Puzzle Questions for Banking

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-0378596412-2"><b>Puzzle Questions Overview</b></h2><p>Puzzle Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Puzzle Questions.</p><h2 id="content-id-8234059617-3"><b>Puzzle Questions</b></h2><p>Direction: Read the given information carefully and answer the following questions.

There are 12 members viz. H, I, J, K, L, M, N, O, P, Q, R, and S are working in the company on different designations. The designations in decreasing order are Chairman, President, VP, CEO, COO, CFO, GM, Manager, Assistant manager (AM), Clerk, Trainee, and Peon such that Chairman is the seniormost designation and Peon is the juniormost designation. Some of them are male while some of them are female. Not more than 2 persons of the same gender are adjacent to each other. Only three people sit between J and L who is a female while only one people sit between H and P who is immediately senior to I who is not a President but I is not a female. M is junior to only three people who is a female and four people sit between M and O who is immediately senior to J. An equal number of persons are senior to K and junior to N who is a male. Only two people sit between H and K who is a female and her neighbors are not female. R is junior to S and senior to Q who is a female. O and P are the same gender as Q while J has the opposite gender.
</p><h2 id="content-id-9387645021-4"><b>Question</b></h2><p>Which one is odd?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 87 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>S</p>
</li><li style="color:red;"><p>R</p>
</li><li style="color:red;"><p>H</p>
</li><li style="color:red;"><p>I</p>
</li><li style="color:green;"><p>P</p>
</li></ol> <h2 id="content-id-6342187095-5"><b>Solution</b></h2><p>The correct answer is <strong>Option 5</strong> i.e. <strong>P</strong></p>

<p>1. M is junior to only three people who is a female and four people sit between M and O who is immediately senior to J. (i.e. M is a CEO, O is an AM, and J is a Clerk)</p>

<p>2. Only three people sit between J and L who is a female while only one people sit between H and P who is immediately senior to I who is not a President but I is not a female. (i.e. L is a CFO, H is a COO, P is a GM, and I - Male is a manager)</p>

<table border="1" cellpadding="1" cellspacing="1">
	<tbody>
		<tr>
			<td><strong>Designation</strong></td>
			<td><strong>Person</strong></td>
			<td><strong>Gender</strong></td>
		</tr>
		<tr>
			<td>Chairman</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>President</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>VP</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>CEO</td>
			<td>M</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>COO</td>
			<td>H</td>
			<td> </td>
		</tr>
		<tr>
			<td>CFO</td>
			<td>L</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>GM</td>
			<td>P</td>
			<td> </td>
		</tr>
		<tr>
			<td>Manager</td>
			<td>I</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>AM</td>
			<td>O</td>
			<td> </td>
		</tr>
		<tr>
			<td>Clerk</td>
			<td>J</td>
			<td> </td>
		</tr>
		<tr>
			<td>Trainee</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>Peon</td>
			<td> </td>
			<td> </td>
		</tr>
	</tbody>
</table>

<p>3. Only two people sit between H and K who is a female and her neighbors are not female. (i.e. K is a President and her neighbor are males)</p>

<p>4. An equal number of persons are senior to K and junior to N who is a male. (i.e. N - Trainee)</p>

<p>5. R is junior to S and senior to Q who is a female. (i.e. R - VP, S - Chairman, and Q - Peon)</p>

<p>6. O and P are the same genders as Q while J has the opposite gender. (i.e. O and P is female, and J is male)(So, the remaining person H is a male because not more than 2 persons of the same gender are adjacent to each other)</p>

<table border="1" cellpadding="1" cellspacing="1">
	<tbody>
		<tr>
			<td><strong>Designation</strong></td>
			<td><strong>Person</strong></td>
			<td><strong>Gender</strong></td>
		</tr>
		<tr>
			<td>Chairman</td>
			<td>S</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>President</td>
			<td>K</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>VP</td>
			<td>R</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>CEO</td>
			<td>M</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>COO</td>
			<td>H</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>CFO</td>
			<td>L</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>GM</td>
			<td>P</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>Manager</td>
			<td>I</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>AM</td>
			<td>O</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>Clerk</td>
			<td>J</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>Trainee</td>
			<td>N</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>Peon</td>
			<td>Q</td>
			<td>Female</td>
		</tr>
	</tbody>
</table>

<p>This is our final arrangement.</p>

<p>Except for P, all are male.</p>

<p>Hence, the correct answer is "<strong>P</strong>".</p>
</body></html>


Which one is odd - Puzzle Questions for Banking

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-6189523704-2"><b>Puzzle Questions Overview</b></h2><p>Puzzle Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Puzzle Questions.</p><h2 id="content-id-6523970148-3"><b>Puzzle Questions</b></h2><p>Direction: Read the given information carefully and answer the following questions.

There are 12 members viz. H, I, J, K, L, M, N, O, P, Q, R, and S are working in the company on different designations. The designations in decreasing order are Chairman, President, VP, CEO, COO, CFO, GM, Manager, Assistant manager (AM), Clerk, Trainee, and Peon such that Chairman is the seniormost designation and Peon is the juniormost designation. Some of them are male while some of them are female. Not more than 2 persons of the same gender are adjacent to each other. Only three people sit between J and L who is a female while only one people sit between H and P who is immediately senior to I who is not a President but I is not a female. M is junior to only three people who is a female and four people sit between M and O who is immediately senior to J. An equal number of persons are senior to K and junior to N who is a male. Only two people sit between H and K who is a female and her neighbors are not female. R is junior to S and senior to Q who is a female. O and P are the same gender as Q while J has the opposite gender.
</p><h2 id="content-id-6508297341-4"><b>Question</b></h2><p>Who among the following is a COO?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 88 Seconds </h3></div></div><b> Options :</b><ol><li style="color:green;"><p>H</p>
</li><li style="color:red;"><p>P</p>
</li><li style="color:red;"><p>I</p>
</li><li style="color:red;"><p>S</p>
</li><li style="color:red;"><p>K</p>
</li></ol> <h2 id="content-id-1947860523-5"><b>Solution</b></h2><p>The correct answer is <strong>Option 1</strong> i.e. <strong>H</strong></p>

<p>1. M is junior to only three people who is a female and four people sit between M and O who is immediately senior to J. (i.e. M is a CEO, O is an AM, and J is a Clerk)</p>

<p>2. Only three people sit between J and L who is a female while only one people sit between H and P who is immediately senior to I who is not a President but I is not a female. (i.e. L is a CFO, H is a COO, P is a GM, and I - Male is a manager)</p>

<table border="1" cellpadding="1" cellspacing="1">
	<tbody>
		<tr>
			<td><strong>Designation</strong></td>
			<td><strong>Person</strong></td>
			<td><strong>Gender</strong></td>
		</tr>
		<tr>
			<td>Chairman</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>President</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>VP</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>CEO</td>
			<td>M</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>COO</td>
			<td>H</td>
			<td> </td>
		</tr>
		<tr>
			<td>CFO</td>
			<td>L</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>GM</td>
			<td>P</td>
			<td> </td>
		</tr>
		<tr>
			<td>Manager</td>
			<td>I</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>AM</td>
			<td>O</td>
			<td> </td>
		</tr>
		<tr>
			<td>Clerk</td>
			<td>J</td>
			<td> </td>
		</tr>
		<tr>
			<td>Trainee</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>Peon</td>
			<td> </td>
			<td> </td>
		</tr>
	</tbody>
</table>

<p>3. Only two people sit between H and K who is a female and her neighbors are not female. (i.e. K is a President and her neighbor are males)</p>

<p>4. An equal number of persons are senior to K and junior to N who is a male. (i.e. N - Trainee)</p>

<p>5. R is junior to S and senior to Q who is a female. (i.e. R - VP, S - Chairman, and Q - Peon)</p>

<p>6. O and P are the same genders as Q while J has the opposite gender. (i.e. O and P is female, and J is male)(So, the remaining person H is a male because not more than 2 persons of the same gender are adjacent to each other)</p>

<table border="1" cellpadding="1" cellspacing="1">
	<tbody>
		<tr>
			<td><strong>Designation</strong></td>
			<td><strong>Person</strong></td>
			<td><strong>Gender</strong></td>
		</tr>
		<tr>
			<td>Chairman</td>
			<td>S</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>President</td>
			<td>K</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>VP</td>
			<td>R</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>CEO</td>
			<td>M</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>COO</td>
			<td>H</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>CFO</td>
			<td>L</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>GM</td>
			<td>P</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>Manager</td>
			<td>I</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>AM</td>
			<td>O</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>Clerk</td>
			<td>J</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>Trainee</td>
			<td>N</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>Peon</td>
			<td>Q</td>
			<td>Female</td>
		</tr>
	</tbody>
</table>

<p>This is our final arrangement.</p>

<p>Clearly, H is a COO.</p>

<p>Hence, the correct answer is "<strong>H</strong>".</p>
</body></html>


<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-6017432589-2"><b>Puzzle Questions Overview</b></h2><p>Puzzle Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Puzzle Questions.</p><h2 id="content-id-4329180756-3"><b>Puzzle Questions</b></h2><p>Direction: Read the given information carefully and answer the following questions.

There are 12 members viz. H, I, J, K, L, M, N, O, P, Q, R, and S are working in the company on different designations. The designations in decreasing order are Chairman, President, VP, CEO, COO, CFO, GM, Manager, Assistant manager (AM), Clerk, Trainee, and Peon such that Chairman is the seniormost designation and Peon is the juniormost designation. Some of them are male while some of them are female. Not more than 2 persons of the same gender are adjacent to each other. Only three people sit between J and L who is a female while only one people sit between H and P who is immediately senior to I who is not a President but I is not a female. M is junior to only three people who is a female and four people sit between M and O who is immediately senior to J. An equal number of persons are senior to K and junior to N who is a male. Only two people sit between H and K who is a female and her neighbors are not female. R is junior to S and senior to Q who is a female. O and P are the same gender as Q while J has the opposite gender.
</p><h2 id="content-id-3186947502-4"><b>Question</b></h2><p>Which among the following designation does P work?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 89 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>COO</p>
</li><li style="color:red;"><p>CFO</p>
</li><li style="color:green;"><p>GM</p>
</li><li style="color:red;"><p>Manager</p>
</li><li style="color:red;"><p>Trainee</p>
</li></ol> <h2 id="content-id-9807631245-5"><b>Solution</b></h2><p>The correct answer is <strong>Option 3</strong> i.e. <strong>GM</strong></p>

<p>1. M is junior to only three people who is a female and four people sit between M and O who is immediately senior to J. (i.e. M is a CEO, O is an AM, and J is a Clerk)</p>

<p>2. Only three people sit between J and L who is a female while only one people sit between H and P who is immediately senior to I who is not a President but I is not a female. (i.e. L is a CFO, H is a COO, P is a GM, and I - Male is a manager)</p>

<table border="1" cellpadding="1" cellspacing="1">
	<tbody>
		<tr>
			<td><strong>Designation</strong></td>
			<td><strong>Person</strong></td>
			<td><strong>Gender</strong></td>
		</tr>
		<tr>
			<td>Chairman</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>President</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>VP</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>CEO</td>
			<td>M</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>COO</td>
			<td>H</td>
			<td> </td>
		</tr>
		<tr>
			<td>CFO</td>
			<td>L</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>GM</td>
			<td>P</td>
			<td> </td>
		</tr>
		<tr>
			<td>Manager</td>
			<td>I</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>AM</td>
			<td>O</td>
			<td> </td>
		</tr>
		<tr>
			<td>Clerk</td>
			<td>J</td>
			<td> </td>
		</tr>
		<tr>
			<td>Trainee</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>Peon</td>
			<td> </td>
			<td> </td>
		</tr>
	</tbody>
</table>

<p>3. Only two people sit between H and K who is a female and her neighbors are not female. (i.e. K is a President and her neighbor are males)</p>

<p>4. An equal number of persons are senior to K and junior to N who is a male. (i.e. N - Trainee)</p>

<p>5. R is junior to S and senior to Q who is a female. (i.e. R - VP, S - Chairman, and Q - Peon)</p>

<p>6. O and P are the same genders as Q while J has the opposite gender. (i.e. O and P is female, and J is male)(So, the remaining person H is a male because not more than 2 persons of the same gender are adjacent to each other)</p>

<table border="1" cellpadding="1" cellspacing="1">
	<tbody>
		<tr>
			<td><strong>Designation</strong></td>
			<td><strong>Person</strong></td>
			<td><strong>Gender</strong></td>
		</tr>
		<tr>
			<td>Chairman</td>
			<td>S</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>President</td>
			<td>K</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>VP</td>
			<td>R</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>CEO</td>
			<td>M</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>COO</td>
			<td>H</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>CFO</td>
			<td>L</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>GM</td>
			<td>P</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>Manager</td>
			<td>I</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>AM</td>
			<td>O</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>Clerk</td>
			<td>J</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>Trainee</td>
			<td>N</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>Peon</td>
			<td>Q</td>
			<td>Female</td>
		</tr>
	</tbody>
</table>

<p>This is our final arrangement.</p>

<p>Clearly, P work as a GM.</p>

<p>Hence, the correct answer is "<strong>GM</strong>".</p>
</body></html>


Which among the following - Puzzle Questions for Banking

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<html><body><h2 id="content-id-9714308265-2"><b>Puzzle Questions Overview</b></h2><p>Puzzle Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Puzzle Questions.</p><h2 id="content-id-7486035129-3"><b>Puzzle Questions</b></h2><p>Direction: Read the given information carefully and answer the following questions.

There are 12 members viz. H, I, J, K, L, M, N, O, P, Q, R, and S are working in the company on different designations. The designations in decreasing order are Chairman, President, VP, CEO, COO, CFO, GM, Manager, Assistant manager (AM), Clerk, Trainee, and Peon such that Chairman is the seniormost designation and Peon is the juniormost designation. Some of them are male while some of them are female. Not more than 2 persons of the same gender are adjacent to each other. Only three people sit between J and L who is a female while only one people sit between H and P who is immediately senior to I who is not a President but I is not a female. M is junior to only three people who is a female and four people sit between M and O who is immediately senior to J. An equal number of persons are senior to K and junior to N who is a male. Only two people sit between H and K who is a female and her neighbors are not female. R is junior to S and senior to Q who is a female. O and P are the same gender as Q while J has the opposite gender.
</p><h2 id="content-id-3168592047-4"><b>Question</b></h2><p>Who among the following works on the juniormost designation?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 89 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>S</p>
</li><li style="color:red;"><p>K</p>
</li><li style="color:red;"><p>N</p>
</li><li style="color:green;"><p>Q</p>
</li><li style="color:red;"><p>J</p>
</li></ol> <h2 id="content-id-1307845296-5"><b>Solution</b></h2><p>The correct answer is <strong>Option 4</strong> i.e. <strong>Q</strong></p>

<p>1. M is junior to only three people who is a female and four people sit between M and O who is immediately senior to J. (i.e. M is a CEO, O is an AM, and J is a Clerk)</p>

<p>2. Only three people sit between J and L who is a female while only one people sit between H and P who is immediately senior to I who is not a President but I is not a female. (i.e. L is a CFO, H is a COO, P is a GM, and I - Male is a manager)</p>

<table border="1" cellpadding="1" cellspacing="1">
	<tbody>
		<tr>
			<td><strong>Designation</strong></td>
			<td><strong>Person</strong></td>
			<td><strong>Gender</strong></td>
		</tr>
		<tr>
			<td>Chairman</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>President</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>VP</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>CEO</td>
			<td>M</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>COO</td>
			<td>H</td>
			<td> </td>
		</tr>
		<tr>
			<td>CFO</td>
			<td>L</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>GM</td>
			<td>P</td>
			<td> </td>
		</tr>
		<tr>
			<td>Manager</td>
			<td>I</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>AM</td>
			<td>O</td>
			<td> </td>
		</tr>
		<tr>
			<td>Clerk</td>
			<td>J</td>
			<td> </td>
		</tr>
		<tr>
			<td>Trainee</td>
			<td> </td>
			<td> </td>
		</tr>
		<tr>
			<td>Peon</td>
			<td> </td>
			<td> </td>
		</tr>
	</tbody>
</table>

<p>3. Only two people sit between H and K who is a female and her neighbors are not female. (i.e. K is a President and her neighbor are males)</p>

<p>4. An equal number of persons are senior to K and junior to N who is a male. (i.e. N - Trainee)</p>

<p>5. R is junior to S and senior to Q who is a female. (i.e. R - VP, S - Chairman, and Q - Peon)</p>

<p>6. O and P are the same genders as Q while J has the opposite gender. (i.e. O and P is female, and J is male)(So, the remaining person H is a male because not more than 2 persons of the same gender are adjacent to each other)</p>

<table border="1" cellpadding="1" cellspacing="1">
	<tbody>
		<tr>
			<td><strong>Designation</strong></td>
			<td><strong>Person</strong></td>
			<td><strong>Gender</strong></td>
		</tr>
		<tr>
			<td>Chairman</td>
			<td>S</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>President</td>
			<td>K</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>VP</td>
			<td>R</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>CEO</td>
			<td>M</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>COO</td>
			<td>H</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>CFO</td>
			<td>L</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>GM</td>
			<td>P</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>Manager</td>
			<td>I</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>AM</td>
			<td>O</td>
			<td>Female</td>
		</tr>
		<tr>
			<td>Clerk</td>
			<td>J</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>Trainee</td>
			<td>N</td>
			<td>Male</td>
		</tr>
		<tr>
			<td>Peon</td>
			<td>Q</td>
			<td>Female</td>
		</tr>
	</tbody>
</table>

<p>This is our final arrangement.</p>

<p>Clearly, Q is a peon(juniormost designation).</p>

<p>Hence, the correct answer is "<strong>Q</strong>".</p>
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Who among the following works - Puzzle Questions for Banking

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<html><body><h2 id="content-id-9815762403-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-4507398261-3"><b>Question</b></h2><p>If tan 3x = cot(30º + 2x), then what is the value of x?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 27 Seconds </h3></div></div><b> Options :</b><ol><li style="color:green;"><p>12º</p>
</li><li style="color:red;"><p>18º</p>
</li><li style="color:red;"><p>10º</p>
</li><li style="color:red;"><p>15º</p>
</li></ol> <h2 id="content-id-4739205861-4"><b>Solution</b></h2><p>The correct answer is <strong>Option 1</strong> i.e. <strong>12º</strong></p>

<p>We know that,</p>

<p>When tan A = cot B, then A + B = 90°</p>

<p>Since, </p>

<p>tan 3x = cot(30º + 2x)</p>

<p>∴ 3x + 30º + 2x = 90°</p>

<p>⇒ 5x = 60°</p>

<p>⇒ x = 12°</p>
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If tan 3x cot 30 2x - Trigonometry Questions for Banking

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<html><body><h2 id="content-id-1528409736-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-9271453068-3"><b>Question</b></h2><p>If tan 2A = cot (A - 21º), where 2A is an acute angle, find A.
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 28 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>35º</p>
</li><li style="color:red;"><p>41º</p>
</li><li style="color:red;"><p>39º</p>
</li><li style="color:green;"><p>37º</p>
</li></ol> <h2 id="content-id-9580743162-4"><b>Solution</b></h2><p>The correct answer is <strong>O</strong><strong>ption 4</strong> i.e. <strong>37º</strong></p>

<table border="1" cellpadding="1" cellspacing="1" style="width:300px">
	<tbody>
		<tr>
			<td>Understanding/Application</td>
		</tr>
		<tr>
			<td>
			<p>tan 2A = cot (A - 21º)</p>

			<p>tan 2A = tan [90º - (A - 21º)]    [since, tan(90º - θ) = cot θ]</p>

			<p>⇒ tan 2A = tan [90º - (A - 21º)] </p>

			<p>⇒ 2A =  [90º - (A - 21º)] </p>

			<p>⇒ 2A =  [90º - A + 21º] </p>

			<p>⇒ 2A =  [111º - A] </p>

			<p>⇒ 2A + A =  [111º] </p>

			<p>⇒ 3A =  [111º] </p>

			<p>⇒ A =  37º</p>
			</td>
		</tr>
	</tbody>
</table>
</body></html>


If tan 2A cot A - 21 - Trigonometry Questions for Banking

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<html><body><h2 id="content-id-4098765321-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-8435629017-3"><b>Question</b></h2><p>If tan (θ1 + θ2) = √3 and Sec (θ1 - θ2) = 2/√3, then what is the value of sin 2θ1 + tan 3θ2?

where [0º < (θ1 - θ2)  < (θ1 + θ2) < 90º]
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 36 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>1</p>
</li><li style="color:green;"><p>2</p>
</li><li style="color:red;"><p>√3</p>
</li><li style="color:red;"><p>2/√3</p>
</li></ol> <h2 id="content-id-8179350642-4"><b>Solution</b></h2><p>The correct answer is <strong>option 2</strong> i.e. <strong>2</strong></p>

<p>Sin 90º = 1, Tan 45º = 1, Tan 60º = √3, Sec 30º = 2/√3</p>

<p>tan (θ<sub>1</sub> + θ<sub>2</sub>) = √3</p>

<p>or</p>

<p>tan (θ<sub>1</sub> + θ<sub>2</sub>) = tan 60º</p>

<p>(θ<sub>1</sub> + θ<sub>2</sub>) = 60º .... (i)</p>

<p>Similarly,</p>

<p>Sec (θ<sub>1</sub> - θ<sub>2</sub>) = 2/√3</p>

<p>Sec (θ<sub>1</sub> - θ<sub>2</sub>) = sec 30º</p>

<p>(θ<sub>1</sub> - θ<sub>2</sub>) = 30º ... (ii)</p>

<p>Adding equation (i) and (ii)</p>

<p>(θ<sub>1</sub> + θ<sub>2</sub>) + (θ<sub>1</sub> - θ<sub>2</sub>)  = 60º + 30º</p>

<p><span style="font-size:12.0pt">⇒ </span>2θ<sub>1</sub> = 90º</p>

<p><span style="font-size:12.0pt">⇒ </span>θ<sub>1</sub> = 45º</p>

<p>Put value of θ<sub>1</sub> in equation (i)</p>

<p>we get, θ<sub>2</sub> = 60º + 45º = 15º</p>

<p>Now, </p>

<p>[sin (2 × 45º)] + [tan (3 × 15º)]</p>

<p><span style="font-size:12.0pt">⇒ </span>sin 90º + tan 45º = 1 + 1 = 2</p>
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If tan 1 2 3 - Trigonometry Questions for Banking

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<html><body><h2 id="content-id-9347165802-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-8016352974-3"><b>Question</b></h2><p>What is the value of {[sin (x + y) – 2 sin x + sin (x – y)]/[cos (x – y) + cos (x + y) – 2 cos x]} × [(sin 10x – sin 8x)/(cos 10x + cos 8x)]?
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 33 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>0</p>
</li><li style="color:green;"><p>tan<sup>2</sup>x</p>
</li><li style="color:red;"><p>1</p>
</li><li style="color:red;"><p>2 tan x</p>
</li></ol> <h2 id="content-id-2516478093-4"><b>Solution</b></h2><p>The correct answer is <strong>option 2 </strong>i.e. <strong>tan<sup>2</sup>x</strong></p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/Urgent%20Diagram_29.04.2021_D1.png" style="height:33px; width:250px"></p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/Urgent%20Diagram_29.04.2021_D2.png" style="height:30px; width:380px"></p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/Urgent%20Diagram_29.04.2021_D3.png" style="height:34px; width:180px"></p>

<p><img alt="" src="https://hranker.com/admin/assets/uploads/ckeditor/Urgent%20Diagram_29.04.2021_D4.png" style="height:33px; width:150px"></p>

<p>= tanx × tanx</p>

<p>= tan<sup>2</sup>x</p>
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What is the value of sin - Trigonometry Questions for Banking

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<html><body><h2 id="content-id-9132857460-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-2763548190-3"><b>Question</b></h2><p>If [(2 sinθ - cosθ)/(cosθ + sinθ)] = 1, then find the value of cotθ.
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 28 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>1/3</p>
</li><li style="color:red;"><p>3</p>
</li><li style="color:green;"><p>1/2</p>
</li><li style="color:red;"><p>2</p>
</li></ol> <h2 id="content-id-7615320894-4"><b>Solution</b></h2><p> The correct answer is <strong>option 3</strong> i.e. <strong>1/2</strong></p>

<table border="1" cellpadding="1" cellspacing="1" style="width:300px">
	<tbody>
		<tr>
			<td>Application</td>
		</tr>
		<tr>
			<td>
			<p>[(2 sinθ - cosθ)/(cosθ + sinθ)] = 1</p>

			<p>⇒ (2 sinθ - cosθ) = 1(cosθ + sinθ)</p>

			<p>⇒ (2 sinθ - cosθ) = (cosθ + sinθ).</p>

			<p>⇒ 2 sinθ - sinθ = cosθ + cosθ</p>

			<p>⇒ sinθ = 2 cosθ</p>

			<p>⇒ cosθ/sinθ = 1/2</p>

			<p>⇒ cotθ = 1/2        [(cosθ/sinθ) = cotθ]</p>
			</td>
		</tr>
	</tbody>
</table>
</body></html>


If 2 sin - cos cos - Trigonometry Questions for Banking

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<html><body><h2 id="content-id-2518749063-2"><b>Trigonometry Questions Overview</b></h2><p>Trigonometry Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Trigonometry Questions.</p><h2 id="content-id-2136590748-3"><b>Question</b></h2><p>Evaluate: 

[(sin 70º/cos 20º) + (cosec 20º/sec 70º) - (2cos 70º × cosec 20º)]
</p><div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 28 Seconds </h3></div></div><b> Options :</b><ol><li style="color:red;"><p>-1</p>
</li><li style="color:red;"><p>1</p>
</li><li style="color:green;"><p>0</p>
</li><li style="color:red;"><p>2</p>
</li></ol> <h2 id="content-id-0279843165-4"><b>Solution</b></h2><p>The correct answer is <strong>option 3</strong> i.e. <strong>0</strong></p>

<table border="1" cellpadding="1" cellspacing="1" style="width:300px">
	<tbody>
		<tr>
			<td>Understanding/Application</td>
		</tr>
		<tr>
			<td>
			<p>[(sin 70º/cos 20º) + (cosec 20º/sec 70º) - (2cos 70º × cosec 20º)]</p>

			<p>By complementary angle</p>

			<p>= [{(sin 90º - 20º)/cos 20º} + {(cosec 90º - 70º)/sec 70º} - {2(cos 90º - 20º) × cosec 20º}]</p>

			<p>= [(cos 20º/cos 20º) + (sec 70º/sec 70º) - (2sin 20º) × (1/sin 20º)]</p>

			<p>= [ 1 + 1 - 2(1)]</p>

			<p>= [2 - 2]</p>

			<p>= 0</p>
			</td>
		</tr>
	</tbody>
</table>
</body></html>
