Experienced professional with 4+ years in Content Marketing. Passionate about learning and knowledge-sharing. 

Marketing Content Specialist

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><h2 id="content-id-2518694703-2">Probability Questions Overview</h2>Probability Questions have a good weightage in the Banking Exam and the type of question asked in Banking exam is similar to the question mentioned below. It has been solved and explained by Gargi.ai Experts and they have tried to elaborate the concept used in Probability Questions.<h2 id="content-id-0487962135-3">Question</h2>Given 3 different red dyes, 4 different blue dyes, and 5 different green dyes, how many combinations of dyes can be made taking atleast one green and one blue dye?
<div class="row show--dificulty--bar" style="margin-top:8px;"><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex !important;border-right:0.1px solid #eee;"><h3 style="font-size:12px !important;">Difficulty : Moderate </h3></div><div class="col-sm-6 show--dificulty--bar" style="display:inline-flex;"><h3 style="font-size:12px !important;"> Average Time : 31 Seconds </h3></div></div> Options :<ol><li style="color:red;">2720
</li><li style="color:red;">3250
</li><li style="color:red;">31
</li><li style="color:red;">4230
</li><li style="color:green;">3720
</li></ol> <h2 id="content-id-5974602318-4">Solution</h2>The correct answer is Option 5 i.e. 3720

<table class="Table" style="width:500px">
	<tbody>
		<tr>
			<td style="height:2px">
			Concept
			</td>
			<td style="height:2px">
			Understanding
			</td>
			<td style="height:2px">
			Application
			</td>
			<td style="height:2px">
			Fair Calculation
			</td>
			<td style="height:2px">
			Rough Calculation
			</td>
		</tr>
		<tr>
			<td rowspan="4">
			Permutation and combination 
			</td>
			<td rowspan="4">
			Atleast 1 green dye can be selected out of 5 green dyes in (25 - 1) i.e. 31 ways

			Similarly, atleast one blue dye can be selected out of 4 in (24 - 1) i.e. 15 ways

			Similarly, atleast 1 red or no red dye can be selected out of 3 red dyes in 23 i.e. 8 ways

			
			</td>
			<td colspan="1" rowspan="4">
			∴ The required number of ways
			</td>
			<td colspan="1" rowspan="4">
			31 × 15 × 8 = 3720
			</td>
			<td colspan="1" rowspan="4">
			
			</td>
		</tr>
	</tbody>
</table>
</body></html>

One stop for all the aspirants of Government exam like SSC, Banking, Railways and Other exams.

Best Online Portal for All Government Exams

Given 3 different red dyes - Probability Questions for Banking

Latest Notifications

Exam Dates

Exam Eligibility

Exam Pattern

Exam Cutoff

Answer Key

Admit Card

Exam Results

Syllabus

Question Answer

Which among the following - Puzzle Questions for Banking

Who among the following book - Puzzle Questions for Banking

The correct answer is Option 5 i.e. 3720 Concept Understanding Application Fair - Probability Questions are asked in Banking exams and your question has been explained by Gargi.ai experts.

Given 3 different red dyes - Probability Questions for Banking

Probability Questions Comments:

Probability Questions RELATED ARTICLES